Draw a line DE =6.5cm, construct the perpendicular bisector od DE. Mark the intersection point as O. With O as center and radius 2.8 cm cut the perpendicular bisector ay B and N. Join BE, EN, ND and DB to get required rhombus.
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\begin{gathered}:\implies\sf \Bigg\{\dfrac{3x + 6}{4x + 6}\Bigg\} = \Bigg\{\dfrac{4}{5}\Bigg\} \\\\\\:\implies\sf 5\Big\{3x + 6\Big\} = 4\Big\{4x + 6\Big\} \\\\\\:\implies\sf 15x + 30 = 16x + 24\\\\\\:\implies\sf 15x - 16x = 24 - 30\\\\\\:\implies\sf \cancel{-}\;x =\cancel{ -}\;6\\\\\\:\implies\underline{\pink{\boxed{\pmb{\frak{x = 6}}}}}\;\bigstar\end{gathered}
:⟹{
4x+6
3x+6
}={
5
4
}
:⟹5{3x+6}=4{4x+6}
:⟹15x+30=16x+24
:⟹15x−16x=24−30
:⟹
−
x=
−
6
:⟹
x=6
x=6
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