Draw a line p . Draw a line q which is parallel to line p at a distance of 4.8cm from it.
Answers
Answer:
The graph in Question shows the positive acceleration.
How To Determine ?
Acceleration may be Positive and Constant or Negative and Constant for a uniformly accelerated motion.
Both the cases are discussed below;
❒ Case 1 :-
\bf \purple{ \maltese \: \: Acc. \: is \: + ve \: and \: Const.}✠Acc.is+veandConst.
⇝ Subcase 1 :-
★ When Positive Velocity is Increasing.
Positive Velocity is Increasing,
⟹ Slope of displacement - time graph is positive and increasing.
The Shape Displacement - time graph will be parabolic : x ∝ t².
a = +ve Constant
\sf \frac{dv}{dt}dtdv = +ve Constant
⟹ Slope of velocity - time graph = +ve Constant
⇝ Subcase 2 :-
★ When Negative Velocity is Decreasing.
Negative Velocity is Decreasing,
⟹ Slope of displacement - time graph is negative and decreasing.
The Shape Displacement - time graph will be parabolic : x ∝ t².
a = +ve Constant
\sf \frac{dv}{dt}dtdv = +ve Constant
⟹ Slope of velocity time - graph = +ve Constant
❒ Case 2 :-
\bf \purple{ \maltese \: \: Acc. \: is \: - ve \: and \: Const.}✠Acc.is−veandConst.
⇝ Subcase 1 :-
★ When Positive Velocity is Decreasing.
Positive Velocity is Decreasing,
⟹ Slope of displacement - time graph is positive and decreasing.
The Shape Displacement - time graph will be parabolic : x ∝ t².
a = - ve Constant
\sf \frac{dv}{dt}dtdv = - ve Constant
⟹ Slope of velocity - time graph = - ve Constant
⇝ Subcase 2 :-
★ When Negative Velocity is Increasing.
Negative Velocity is Increasing,
⟹ Slope of displacement - time graph is neagative and increasing.
The Shape Displacement - time graph will be parabolic : x ∝ t².
a = - ve Constant
\sf \frac{dv}{dt}dtdv = - ve Constant
⟹ Slope of velocity - time graph = - ve Constant.