draw a line segement AB=5.5 . find a point P on it such that AP = 2/3 PB
Answers
Step-by-step explanation:
1. Draw a line segment AB = 5.5 cm 2. With A as centre and radius = 6 cm, draw an arc. 3. With B as centre and radius = 4.8 cm draw another arc. 4. Let these arcs meet each other at the point P. PA = 6 cm, PB = 4.8 5. With P as centre and some suitable radius draw an arc meeting AB at the points C and D. 6. With C as centre and radius more than half of CD, draw an arc. 7. With D as centre and same radius as in step 6, draw an arc. 8. Let these arcs meet each other at the point Q. 9. Join PQ. 10. The PQ meet AB at point O. Then PO ⊥ AB i.e; ∠AOP = 90° = ∠POB.Read more on Sarthaks.com - https://www.sarthaks.com/170812/draw-line-segment-mark-point-such-that-pa-cm-and-pb-cm-from-the-point-draw-perpendicular-to-ab
Answer:
Refers to the attachment
