Math, asked by kalaiselvir0105, 6 hours ago

draw a line segment 7.6cm and divide it in ratio 5/8​

Answers

Answered by 72HurricanE
0

Step-by-step explanation:

Steps of construction:

Draw AB = 7.6 cm

Draw ray AX, making an acute angle with AB

Mark 13 (i.e, 5 + 8) points as A₁, A₂ ,A₁₃ on AX such that AA₁ = A₁A₂ = A₂A₃ = A₁₂A₁₃

Join BA₁₃

Through A₅ (since we need 5 parts to 8 parts) draw CA₅ parallel to BA₁₃ where C lies on AB.

Now AC: CB = 5 : 8

By measurement, we find that AC = 2.9 cm and CB = 4.7 cm

Proof:

CA₅ is parallel to BA₁₃

By Basic Proportionality theorem, in ΔAA₁₃B

AC/BC = AA₅/A₅A₁₃ = 5/8 (By Construction)

Thus, C divides AB in the ratio 5:8.

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