draw a line segment AB=5.5cm On AB take any point P. At P,draw a line perpendicular to AB,cut off PQ = 3 cm. through D, draw a line CD||AB.
Answers
Step-by-step explanation:
Steps for Construction :
* Draw a line AB = 5.5 cm
* Taking Point A as radius take radius of 6 cm on Compass and draw an arc
* Now taking Point B as centre take radius 4.8 cm and draw an arc.
*The point at which the two arcs meet is Point P
* Now taking point P take radius of any suitable and draw a semi circle
*Draw a line parallel to AB from point P
* Draw 90° angle on the above drawn line from Point P.
* This will meet AB at a point and form 90° with it also because if one angle between two parallel lines cut by a transversal is 90° then all interior angles = 90°.
HENCE, YOU WILL DRAW THE REQUIRED FIGURE.
Step-by-step explanation:
Steps for Construction :
* Draw a line AB = 5.5 cm
* Taking Point A as radius take radius of 6 cm on Compass and draw an arc
* Now taking Point B as centre take radius 4.8 cm and draw an arc.
*The point at which the two arcs meet is Point P
* Now taking point P take radius of any suitable and draw a semi circle
*Draw a line parallel to AB from point P
* Draw 90° angle on the above drawn line from Point P.
* This will meet AB at a point and form 90° with it also because if one angle between two parallel lines cut by a transversal is 90° then all interior angles = 90°.
HENCE, YOU WILL DRAW THE REQUIRED FIGURE.