.Draw a line segment AB of length 7.4 cm. Mark a point P on it such that AP = 3.6 cm. At P draw a perpendicular to AB using ruler and compass.
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Step-by-step explanation:
hlo mate here's your answer
Steps of Construction:
1.Construct a line segment
AB=
5.8cm.
2.Now mark a point
P
on the line segment
AB
such that
PB=
3.6cm.
3.Taking
P
as centre and some suitable radius construct and arc which meets
AB
at the point
L.
4.Taking
L
as centre and same radius cut off the arcs
LM
and then as
N.
5.Now bisect the arc
MN
at the point
S.
6. Join
PS
and produce it to point
Q.
Here
PQ
is perpendicular to the line segment
AB
at point
P.
I hope its help you mark as brainlist plz ok
Answered by
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Draw a line segment PQ = 7.4 cm.
Draw a line segment PQ = 7.4 cm.From point P and radius of more than half of PQ, draw arcs on either side of PQ.
Draw a line segment PQ = 7.4 cm.From point P and radius of more than half of PQ, draw arcs on either side of PQ.Without changing the radius, cut the previous arcs from point Q.
Draw a line segment PQ = 7.4 cm.From point P and radius of more than half of PQ, draw arcs on either side of PQ.Without changing the radius, cut the previous arcs from point Q.Let the points of intersection of these arcs be X and Y.
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