Question

draw a line segment ab of length 7 cm and find a point P on it such that AP:pb=1:3. measure ap and pb

Answer 1

Answer:

The measure of AP and PB are $\frac{7}{4}$ cm and $\frac{21}{4}$ cm respectively.

Step-by-step explanation:

The length of AB is 7cm.

Point P lies on the line AB, such that AP:PB=1:3.

Let the measure of AP and PB be x and 3x.

$AB=AP+PB$

$7=x+3x$

$7=4x$

$x=\frac{7}{4}$

The measure of AP and PB are

$AP=x=\frac{7}{4}$

$PB=3x=3\times \frac{7}{4}=\frac{21}{4}$

Therefore the measure of AP and PB are $\frac{7}{4}$ cm and $\frac{21}{4}$ cm respectively.

Answer 2

Answer:

AP=1.75cm PB=5.25cm

Step-by-step explanation:

Refer to the above attachement..

Steps of Construction:

1.Draw a line segment AB=7cm

2.At A,Draw angle BAC=60 degree above AB

3.At B,Draw angle ABD=60 degree below AB

4.Mark 1+3=4 points on AC and BD at equal distances and name them A1,A2,A3,A4 and B1,B2,B3 and B4 respectively.

5.Join A to B4 and B to A4.

6.Join A1 to B3 intersecting AB at P

7.Measure AP=1.75cm and PB=5.75cm..

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