Question

draw a line segment AB of length 7 cm and find a point p on it such that AP:PB=1:3. measure AP and PB.

Answer 1

u can do the above construction of dividing the 7cm linesegment into 4 equal parts

Answer 2

Answer:

AP=1.75 cm and PB=5.25 cm

Step-by-step explanation:

It is given that the measure of line segment AB is 7 cm.

A point P divided the line AB in two parts such that AP:PB=1:3.

Let measure of AP and PB are x and 3x respectively.

$AP+PB=AP$                            (Segment addition property)

$x+3x=7$

$4x=7$

Divide both sides by 4.

$\frac{4x}{4}=\frac{7}{4}$

$x=1.75$

The measure of AP is 1.75 cm.

$3x=3\times 1.75=5.25$

The measure of PB is 5.25 cm.