Draw a
line segment of Ab=12 cm and divide
it in the ratio
5: 3 by geometrical
construction
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Answer:
Let AB be our given line segment.
To construct:
Divide AB in the ratio of 3 : 5.
Steps of construction
1) Draw AB.
2) Draw AX, making an acute angle with AB.
3) Locate 8(= 3 + 5) points A1,A2,A3,A4,A5,A6,A7 and A8 on AX
so that AA1=A1A2=A2A3=A3A4=A4A5=A5A6=A6A7=A7A8.
4) Join BA8.
5) Through the point A3 draw a line parallel to A8B
(By making an angle equal to ∠AA8B) at A3 intersecting AB at the point C.
Then AC : CB = 3 : 5.
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