Question

Draw a line segment of length 10 cm and divide it in the ratio of 3:5 internally.

Answer 1

Firstly Draw a line segment AB of 10cm
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Ratio given = 3:5
Let the numbers in the ratio be 3x and 5x

According to ques.
3x + 5x = 10
8x = 10
x =10/8
So, 3x = 10/8 × 3= 3.75
& 5x = 10/8 × 5= 6.25
Dividing length = either 3.7 cm or 6.3 cm
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use a compass and draw an arc of 3.7 cm from point A of the line segment .
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Hope it will help you !!!

Answer 2

Answer:

length of two parts is 6 cm and 4 cm.

Step-by-step explanation:

• ·First draw a line segment AB of length 10 cm.

• now from point A, at some angle, draw a random line of any length more than half of AB(for better marking)

• using compass, keep the centre as A and cut an arc of any length on this new line.

• keep the point of intersection as centre and repeat this to get 5 equally spaced points on new line AC

• join the 5th point from A on line segment AC to B

• draw a line, parallel to this DB line from 3rd point onto the line segment AB.

this divides it in 3:2 ratio.

measuring this we get length as 6cm and 4 cm.