Question

Draw a line segment of length 5.3cm and draw it's perpendicular bisector.​

Answer 1

Answer:

•Draw a line segment with 5.3 cm length.

•Using compass take length with more than half draw arcs at point A and B as shown in the construction.

•join the intersecting points and it intersects at a point.

•That point is our required perpendicular bisector point.

hope you understand ✨

Answer 2

First method :

$\fbox\orange{Steps\: of \:Construction :}$

1. Draw a line segment AB = 5.3 cm
2. With A as centre and radius equal to more than half of AB, draw arcs on both sides of AB.
3. With B as centre and with the same radius as taken in step 2, draw arcs on both the sides of AB.
4. Let the arcs intersect each other at points P and Q.
5. Join P and Q.
6. The line PQ cuts the given line segment AB at the point O.
7. Thus, PQ is a bisector of AB such that
8. OA = OB =$\frac { 1 }{ 2 } AB$

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Second Method :

$\fbox\red{Steps \:of \:Construction :}$

1. Draw the given line segment AB = 5.3 cm.
2. At A, construct ∠PAB of any suitable measure. Then ∠PAB = 60° construct ∠QBA = 60°
3. From AP, cut AR of any suitable length and from BQ ; cut BS = AR.
4. Join R and S
5. Let RS cut the given line segment AB at the point O.
6. Thus RS is a bisector of AB such that OA = OB = $\frac { 1 }{ 2 } AB$