draw a line segment of length 6cm using compasses and ruler,find a point P on it which divides it in the ratio 3:4
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1. Draw a segment AB of length 6cm.
2. By putting your compass on A and B, draw a perpendicular bisector of AB. (Shown in figure) The bisector divides the segment into half.
3. Perpendicular bisector meets AB at a point. Name it O.
4. By putting your compass on O and B, draw a perpendicular bisector of OB. (Shown in figure)
5. Perpendicular bisector meets OB at a point. Name it P.
P divides the segment into 3:4
AP = ¾ of AB
HOPE IT HELPS YOU!
PLS MARK AS BRAINLIEST
2. By putting your compass on A and B, draw a perpendicular bisector of AB. (Shown in figure) The bisector divides the segment into half.
3. Perpendicular bisector meets AB at a point. Name it O.
4. By putting your compass on O and B, draw a perpendicular bisector of OB. (Shown in figure)
5. Perpendicular bisector meets OB at a point. Name it P.
P divides the segment into 3:4
AP = ¾ of AB
HOPE IT HELPS YOU!
PLS MARK AS BRAINLIEST
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Given:
We have given line segment of length 6cm.
To Find:
We need to divide it in 3:4?
Step-by-step explanation:
- First of all we start with Draw a line segment of 6cm in length and draw a ray AX making an acute angle with line segment AB.
- Locate 7=(3+4) points, on AX such that all are equal in their length.
- Now join B.
- Through the point , draw a parralel line to (by making an angle equal to angleAB) intersecting AB at C.
- C isn the point dividing the segment AB of 6 cm into 3 ratio 4.
Thus we get the required result.( see diagram attached)
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