Question

Draw a line segment of length 7.8 cm and divide it in the ratio 5:8. Measure
the two parts.​

Answer 1

ANSWER:

*DRAW A LINE SEGMENT AB = 7.8 CM

*DRAW AN ACUTE ANGLE FROM 'A' TO 'X'.

*DIVIDE 'AX' INTO 13 EQUAL PARTS ( 5+8=13)

*NAME THEM AS A1,A2,A3 ......….. A13.

*JOIN 'A13' AND 'B'

*DRAW A LINE PARALLEL TO 'A13B' WHICH INTERSECTS 'AB' AT 'C' AND THE POINT 'C' DIVIDES 7.8 CM IS LINE SEGMENT INTO THE RATIO OF 5 : 8.

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Answer 2

The internal division of 5:8 of line segment is attached.

On measurement AC= 3 cm and CB= 4.8 cm

Given:

• A line segment of 7.8 cm.

To find:

• Divide it internally in the ratio 5:8.
• What is the length of each part ?

Solution:

Concept to be used:

Make two same acute angle with line segment and do equal parts of ratios.

Steps of construction:

1. Draw a line segment of 7.8 cm with the help of pencil and scale,say it is AB.
2. Draw an acute angle below AB. let say it is AX.
3. Make 5 equal segments of AX.
4. Draw the same angle from B, let say it is BY.
5. Make 8 equal segments of BX.
6. Join $B_8$ to $A_5$, it cuts AB at point C.
7. The point C divides the line segment AB in 5:8.

Verification:

On measurements it is found that

AC= 3 cm

and

CB= 4.8 cm

Thus,

AC:CB= 5:8

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Learn more :

1) draw a line segment AB=9 cm using a pair of compass find the point C such that AC=BC

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2) Divide the line segment of 7 CM in the ratio 3:4

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