Draw a line segment of trianglelength 7.2 cm and divide it in the ratio 5:3.measure the two parts?
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Draw a line segment of length 7.2 cm and divide it in the ratio 5 : 3. Measure the two parts.
Need to draw a line segment with length 7.2cm
Also, to divide it 5:3 parts. Measure them..
⇒ Let m = 5 and n = 3
1) Draw a ray AX, making an acute angle with AB.
2) Locate 8 = m + n points
A1,A2,A3,A4,A5,A6,A7,A8 on AX such that AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6 = A6A7 = A7A8
3) Join BA8
4) Through the point A5 (m = 5) draw a line parallel to A8B at A5 intersecting AB at the point C. Then AC:CB = 5:3
⇒ Let the ratio be 5x:3x
⇒ 5x + 3X = 7.2cm
⇒ 8x = 7.2cm.
⇒ x = 0.9
⇒ x = 0.9cm.
Substituting ‘x’ value in 5x,3x we get
⇒ 5x = 5 × 0.9
= 4.5cm
⇒ x = 3 × 0.9
= 2.7cm.
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