Question

draw a line segment PQ = 8cm take a point c on PQ such that PC = 1/3CQ​

Answer 1

$PC=\frac{1}{3}CQ$ on line $PQ$.

Step-by-step explanation:

Given,

Line segment $PQ=8cm$ and take a point $C$ on $PQ$ such that $PC=\frac{1}{3}CQ$

Following steps:

• Draw a line segment $PQ=8cm$ using scale.
• From point $P$, draw any angle like $\angle QPX=\theta$

• Divide Line $PQ$ with four equal parts like $X_{1}, X_{2} ,X_{3}$ and $X_{4}$

• Join $QX_{4}$ and also draw a parallel with  $QX_{4}$ through point $X_{1}$ which meet the line $PQ$ at $C$

Now, $PC=\frac{1}{3}CQ$ on line $PQ$.

Answer 2

Answer:pc=1/4pq=2cm

Step-by-step explanation:

pc=1/3cq

3pc=cq

cq+pc=pq

3pc+pc=pq

4pc=pq

pc=1/4pq

construction should be done accordingly

draw pq=8cm

from p draw a slanting line having 5 arcs that are equidistant

join q to the 5th arc

angle formed by p ,point on 5th arc and q should be equal to p 1st arc and a point on line pq

this point on pq would be c

pc=2cm cq=6cm and pq=8cm