draw a line segment PQ of length 5 cm.draw its perpendicular bisector by using compass.
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Step-by-step explanation:
1. Draw a line segment PQ = 5 cm.
2. With any radius greater than 2.5 cm, and compass fixed at A, draw 2 arcs, one above and one below PQ.
3. With the same radius, compass at Q, cut the 2 arcs drawn in step 2.
4. The line joining these two arcs is the perpendicular bisector of PQ.
i.e. RS is the perpendicular bisector of PQ.
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Answer:
Given in the question, a line segment PQ of length 5 cm.
Construction:
- First we draw a line segment PQ of length 5cm.
- So, by using a ruler, we draw a line segment PQ of length 5cm.
- Taking P as a center and take radius more than half of PQ.
- Now, from point P as centre draw two arc with the help of compass.
- Similarly, taking Q as center and take radius more than half of length PQ, draw an arc which cut the previous arc.
- Plot E and F at intersecting point.
- Join E and F by the help of ruler to intersecting PQ at C.
Hence, EF is the perpendicular bisector of PQ.
#SPJ3
Answered by
0
Answer:
Given in the question, a line segment PQ of length 5 cm.
Construction:
- First we draw a line segment PQ of length 5cm.
- So, by using a ruler, we draw a line segment PQ of length 5cm.
- Taking P as a center and take radius more than half of PQ.
- Now, from point P as centre draw two arc with the help of compass.
- Similarly, taking Q as center and take radius more than half of length PQ, draw an arc which cut the previous arc.
- Plot E and F at intersecting point.
- Join E and F by the help of ruler to intersecting PQ at C.
Hence, EF is the perpendicular bisector of PQ.
#SPJ3
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