Math, asked by reenapandey018, 3 months ago

draw a line segment SB Of length 4. 8 cm. Now, construct the perpendicular bisector of the line segment AB.
Please solve it step by step and answer me fast please ​

Answers

Answered by Anonymous
2

Step-by-step explanation:

Steps of Construction:

Steps of Construction:1. Construct a line segment PQ=4.8cm.

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.4. Let the arcs intersect each other at point A and B

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.4. Let the arcs intersect each other at point A and B5. Now join A and B.

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.4. Let the arcs intersect each other at point A and B5. Now join A and B.6. The line AB cuts the line segment PQ at the point O. Here OP=OQ and ∠AOQ=90

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.4. Let the arcs intersect each other at point A and B5. Now join A and B.6. The line AB cuts the line segment PQ at the point O. Here OP=OQ and ∠AOQ=90 o

Steps of Construction:1. Construct a line segment PQ=4.8cm.2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.4. Let the arcs intersect each other at point A and B5. Now join A and B.6. The line AB cuts the line segment PQ at the point O. Here OP=OQ and ∠AOQ=90 o Then the line AB is perpendicular bisector of PQ.

Attachments:
Answered by rishika3105
1

Answer:

Steps of Construction:

1. Construct a line segment PQ=4.8cm.

2. Taking P as center and radius equal than half of PQ, construct arc on both the PQ.

3. TAking Q as center and the same radius as taken in step 2, construct arcs on both sides of PQ.

4. Let the arcs intersect each other at point A and B

5. Now join A and B.

6. The line AB cuts the line segment PQ at the point O. Here OP=OQ and ∠AOQ=90

o

Then the line AB is perpendicular bisector of PQ.

Attachments:
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