Draw a linear pair of angles. Bisect each of the two angles. Verify that the two bisecting rays are perpendicular to each other.
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Step-by-step explanation:
As shown in the attached figure, ∠AOC and ∠BOC form a linear pair, so we have
∠AOC + ∠BOC = 180°.
Ray OP and ray OQ are drawn which bisects ∠AOC and ∠BOC respectively. We are to prove that ∠POQ = 90°.
Therefore, we have
2∠AOP = 2∠COP = ∠AOC and 2∠BOP = 2∠COQ = ∠BOC.
Now,
\begin{gathered}\angle AOC+\angle BOC=180^\circ\\\\\Rightarrow 2\angle POC+2\angle QOC=180^\circ\\\\\Rightarrow \angle POC+\angle QOC=90^\circ\\\\\Rightarrow \angle POQ=90^\circ.\end{gathered}
∠AOC+∠BOC=180
∘
⇒2∠POC+2∠QOC=180
∘
⇒∠POC+∠QOC=90
∘
⇒∠POQ=90
∘
.
Thus, the bisecting rays are perpendicular to each other. Hence verified.
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