Question

draw a pair of linear equations graph 3x+y=7 and 4x-y=7 please send answer​

Answer 1

Answer:

»Question-

draw graph for 3x+y = 7 and 4x -y = 7

$\huge\mathbb\pink{Answer}$

» 3x+y = 7

by putting x as 0

3(0)+y = 7

0+y = 7

y = 7

1st coordinate = (0,7)

by putting x as 3

3(3)+y = 7

9+y = 7

y = 7-9

y = -2

2nd coordinate - (3,-2)

* Note the graph will be a straight line as it is a linear equation.

» 4x -y = 7

by putting x as 2

4(2) - y = 7

8-y = 7

-y = 7-8

-y = -1

y = 1

1st coordinate = (2,1)

by putting x as 1

4(1)-y = 7

-y = 7-4

-y = 3

y = -3

2nd coordinate = (1,-3)

Now for making graph we will connect the points whose coordinates we got.

*Refer the attachment for graph.

★(2,1) is the point of intersection means that it is a common solution.

Answer 2

SolutioN :

We have, Pair of Linear Equation.

$\tt \dagger \: \: \: \: \: 3x + y = 7.$

$\tt \dagger \: \: \: \: \: 4x - y = 7.$

$\rule{90}2$

☯ Taking Equation ( 1 )

$\tt \dagger \: \: \: \: \: 3x + y = 7.$

✎ When, x = 1.

$\tt : \implies3(1) + y = 7.$

$\tt : \implies y = 7 - 3.$

$\tt : \implies y = 4.$

$\rule{90}1$

✎ When, x = 2.

$\tt : \implies3(2) + y = 7.$

$\tt : \implies6 + y = 7.$

$\tt : \implies y = 1.$

$\rule{90}1$

✎ When, x = - 2.

$\tt : \implies3( - 2) + y = 7.$

$\tt : \implies - 6 + y = 7.$

$\tt : \implies y = 7 + 6$

$\tt : \implies y = 13.$

$\rule{200}3$

☯ Taking Equation ( 2 )

$\tt \dagger \: \: \: \: \: 4x - y = 7.$

$\tt : \implies 4x - y = 7.$

$\rule{90}1$

✎ When, x = 1.

$\tt : \implies 4(1) - y = 7.$

$\tt : \implies 4 - y = 7.$

$\tt : \implies - y = 7 - 4$

$\tt : \implies - y = 3 .$

$\tt : \implies y = - 3.$

$\rule{90}1$

✎ When, x = 2.

$\tt : \implies 4(2) - y = 7.$

$\tt : \implies 8 - y = 7.$

$\tt : \implies - y = 7 - 8$

$\tt : \implies y = 1.$

$\rule{90}1$

✎ When, x = - 2.

$\tt : \implies 4( - 2) - y = 7.$

$\tt : \implies - 8 - y = 7.$

$\tt : \implies - y = 7 + 8$

$\tt : \implies y = - 15$

★ Graph Provide above ↑