Draw a pair of parallel lines and a transversal. Verify the above three statements by actually
measuring the angles.
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s = ut + ½at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we know u = 15m/s, v = 0, t = 5s and we want to find a, so we use equation (3)
v = u + at
0 = 15 + 5a
a = -15/5 = -3
The acceleration is -3m/s^2, and the negative sign indicates that it is a retardation
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