Math, asked by haroon3, 1 year ago

Draw a parallelogram ABCD in which AB=6.5 cm , AD = 4.8 cm and angel BAD= 70° , measure its Diagonals.

Answers

Answered by nikhilbastian
297

Since ABCD is a parallelogram, AB = DC = 6.5 cm and AD = BC = 4.8 cm.

Given:

∠A = 70°

Steps of construction:

1. Draw AD equal to 4.8 cm.

2. Make an angle of 70° at A and cut an arc of 6.5 cm. Name it B.

3. Cut an arc of 4.8 cm from B and 6.5 cm from D. Name it C.

4. Join AB, BC and CD.

5. Measuring the diagonal AC and BD, we get AC equal to 9.2 cm and BD equal to 6.6. cm.

Attachments:
Answered by sshashwat
44

Step-by-step explanation:

Since ABCD is a parallelogram,AB=DC=6.5cm and AD=BC=4.8cm

Given

angle=70°

step of construction

1). Draw AD equal to 4.8cm

2).Make and angle of 70° at A and cut and arc of 6.5cm. Name it B.

3).Cut an arc of 4.8cm from B and 6.5cm from D. Name it C .

4). Join AB, BC and CD.

5). Measuring the diagonal AC and BD, we get AC equal to 9.2cm and BD equal to 6.6cm.

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