Math, asked by nileshkumar3141438, 2 months ago

Draw a Parallelogram ABCD in which AB=6,5 cm, AD=4.8 cm and
LBAD = 70 Measure its diagonals .​

Answers

Answered by cool5257boy
1

Answer:

Since ABCD is a parallelogram

∴AB=CD=6.5 cm and

AD=BC=4.8 cm

Given ∠BAD=700

Steps of construction:

1) Draw AD such that AD=4.8 cm

2) Make an angle measuring 700 at A and cut an arc of 6.5 cm and name it as B

3) From B cut an arc of 4.8 cm and 6.5 cm from D, name it as C

4) Join AB,BC and CD

5) By measuring the diagonals AC and BD with a ruler, we get AC=9.2 cm and BD=6.6 cm

Step-by-step explanation:

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Answered by d200876
1

Answer:

Step-by-step explanation:

Since ABCD is a parallelogram, AB = DC = 6.5 cm and AD = BC = 4.8 cm.

Given:

∠A = 70°

Steps of construction:

1. Draw AD equal to 4.8 cm.

2. Make an angle of 70° at A and cut an arc of 6.5 cm. Name it B.

3. Cut an arc of 4.8 cm from B and 6.5 cm from D. Name it C.

4. Join AB, BC and CD.

5. Measuring the diagonal AC and BD, we get AC equal to 9.2 cm and BD equal to 6.6. cm.

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