Draw a parallelogram ABCD in which AB=6.5cm,AD=4.8cm and BAD=70° measure it's diagonals
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Since ABCD is a parallelogram
∴AB=CD=6.5 cm and
AD=BC=4.8 cm
Given ∠BAD=70°
Steps of construction:
1) Draw AD such that AD=4.8 cm
2) Make an angle measuring 70° at A and cut an arc of 6.5 cm and name it as B
3) From B cut an arc of 4.8 cm and 6.5 cm from D, name it as C
4) Join AB,BC and CD
5) By measuring the diagonals AC and BD with a ruler, we get AC=9.2 cm and BD=6.6 cm
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