draw a Parallelogram related :
Answers
Answer:
parallelogram is a special type of quadrilateral that has equal and parallel opposite sides. The given figure shows a parallelogram ABCD which as AB parallel to CD and AD parallel to BC. ... We also see a lot of parallelogram like shapes and objects around us.
Step-by-step explanation:
Answer:
CONSTRUCT A PARALLELOGRAM WHEN TWO CONSECUTIVE SIDES AND THE INCLUDED ANGLE ARE GIVEN - EXAMPLE
concept
Construct a parallelogram ABCD with sides AB = 4 cm and AD = 5 cm and angle A = 60.
Construct a line segment AB = 4 cm. Construct a 60 angle at point A.
Construct a line segment AD = 5 cm on the other arm of the angle. Then, place the sharp point of the compasses at B and make an arc 5 cm above B.
Stretch your compasses to 4 cm, place the sharp end at D and draw an arc to intersect the arc drawn in step 2. Label the intersecting point C. Join C to D and B to C to form the parallelogram ABCD.
CONSTRUCT A PARALLELOGRAM WHEN TWO CONSECUTIVE SIDES AND A DIAGONAL ARE GIVEN - EXAMPLE
concept
Construct a parallelogram ABCD in which AB = 6 cm, BC = 4.5 cm and diagonal AC = 6.8 cm.
Draw AB = 6 cm.
With A as centre and radius 6.8 cm, draw an arc.
With B as center and radius 4.5 cm draw another arc, cutting the previous arc at C.
Join BC and AC.
With A as centre and radius 4.5 cm, draw an arc.
With C as centre and radius 6 cm draw another arc, cutting the previously drawn arc at D.
Join DA and DC.
Then, ABCD is the required parallelogram.
CONSTRUCT A PARALLELOGRAM WHEN ONE SIDE AND TWO DIAGONALS ARE GIVEN - EXAMPLE
concept
Construct a parallelogram ABCD in which AB=7cm,AC=10cm,and BD=8cm
Construct line segment AB of length 7 cm.
From point A, mark an arc taking 5 cm as radius.
From point B, mark an arc taking 4 cm as radius. Name the point of intersection as O. Join AO and OB.
Extend AO and BO. From O, mark an arc on extended ray AO of radius 5 cm. Name it as C.
Similarly mark an arc on extended ray BO of radius 4 cm. Name it as D.
Join AD, DC and BC. ABCD is the required parallelogram.
CONSTRUCTION OF A PARALLELOGRAM GIVEN THE LENGTH OF TWO DIAGONALS AND INTERSECTING ANGLES BETWEEN THEM - EXAMPLE
concept
Construct a parallelogram whose diagonals are 4cm and 5cm and the angle between them is = 70
0
.
First draw a rough diagram of ABCD with AC and BD as diagonals.
Mark a point A and draw a line though A
From A, draw an arc of radius 4cm to cut the above line at C (AC=4cm)
Bisect AC at O (From A and C, draw arcs of radius more than half the length of AC on both sides, Let they cut at X and Y. XY is the perpendicular bisector of AC. It cuts AC at O)
From O, draw a line at an angle 70
0
to AC on both sides
From O, draw an arc of radius 2.5cm on both sides of AC to cut the above line at B and D. Join AB, BC, CD and DA.
ABCD is the required parallelogram.
CONSTRUCTION OF A PARALLELOGRAM GIVEN THE LENGTH OF ADJACENT SIDES AND THE HEIGHT OF PARALLELOGRAM - EXAMPLE
concept
Construct a parallelogram ABCD, with adjacent sides AB=4 cm, BC = 5cm and height corresponding to BC =3.5 cm
Mark a point B and draw a line though B
From B, draw an arc of radius 5cm to cut the above line at C
Draw 2 perpendicular lines XY and PQ on BC at any two points U and T on it.
From U and T cut PQ and XY at S and R by an arc of radius 3.5 cm. Join RS.
Cut the line RS at A by an arc of radius 4cm from B
From A cut the line RS at D by an arc of radius 5cm
ABCD is the required parallelogram.
PARALLELOGRAM WHEN ONE SIDE , A DIAGONAL AND ALTITUDE IS GIVEN - EXAMPLE
concept
Construct a Parallelogram PQRS when PQ=3 cm , Diagonal PR=4.4 cm and an altitude 2.2 cm
Given:PQ=3 cm , Diagonal PR=4.4 cm and an altitude 2.2 cm
Step 1: Draw a line segment PQ=3 cm
Step 2: At Q construct a perpendicular QF
Step 3: Cut off 2.5 cm on QF and locate point T; QT = 2.2 cm . Draw perpendicular to QF at T
Step 4: With P as center and radius 4.4 cm, draw an arc to cut the second perpendicular in R
Step 5: With R as center and radius = PQ draw an arc to cut the line through F and R in S
Step 6: Join PS and QR
The PQRS is the required parallelogram