Question

draw a parallelogram wher AC =6cm ,DB =7.2 cm and the included angle DCE =60°​

Answer 1

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Answer 2

Answer:

Here in the given figure ∠BAC = 60º

And AP = 34×AB = 34×5 cm = 154cmand AQ= 14×AC = 14×7 cm = 74cm

So here two sides and an angle between them is given so using the cosine rule we can get the measure of third side c2=a2+b2− 2 ab cos c so PQ2=AP2+AQ2−2×a×b×cos c⇒PQ2=(154)2+(74)2−2×154×74×COS 60°⇒PQ2=16916⇒PQ = 134cm = 3.25 cm

Now for the 2nd part

As the two triangles are similar then the sides are in proportion

So ABPQ=ACPR=BCQR

AB , AC and PQ is given so PR=(PQ)×(AC)AB=8×66=8cm

Similarly QR=(PQ×BC)AB=(8×5)6=406cm