Draw a plot of variation in quantity of gas adsorbed with the pressure of the gas. Also plot
the graph between log vs log p at constant temperature.
What is the slope of this line?
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11th
Chemistry
States of Matter
Gas Laws
The slope of the graph betw...
CHEMISTRY
The slope of the graph between logP and logV at constant temperature for a given mass of a gas is:
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ANSWER
The gas equation is given by, PV=nRT
Taking log on both side, logPV=lognRT
By expanding,
logP+logV=log(nRT)
logP=(−1)logV+log(nRT)
When the temperature is constant, mass remains constant hence mole is constant, it means nRT is constant.
So, log(nRT) is constant
logP=(−1)logV+log(nRT)
This equation follows as,Y=Mx+C
Where, y=logP x=logV
c=log(nRT) and m=−1
Here m is the slope of the equation.
So, slope = −1
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