Question

Draw a ∆PQR in which PQ = 3.8 cm ,∠Q = 75° and PR = 5 cm. ( Construction steps )​

Answer 1

Answer:

Step-by-step explanation:

1.Draw base BC=5cm

2.Let's draw ∠B=75∘

.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Join $$CD$

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:△ABC is the required triangle.

Answer 2

Step-by-step explanation:

draw a line segment of PR =5 cm

draw a line of PQ=3.8cm

write an angle of Q=75 degree