Draw a ΔPQR, in which QR = 3.5 cm, angle Q= 45°, angle P= 105°?
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Answer:
1. Draw PQ=3.5cm.
2. At P make an angle of 60
o
with the help of compass.
3. At Q draw the angle of 105
o
with the help of protractor. Again by taking Q as centre, draw an arc of 3.5cm which intersects the line segment at R.
4. At R again draw an angle of 120
o
.
i.e.360
o
–(60
o
+105
o
+75
o
)=360
o
–240
o
=120
o
which will intersect the arm of the angle 60
o
at S.
Henc measures.
In Quadrilateral MORE: ℓ(MO)=5.8 cm,ℓ(OR)=4.4 cm,m∠M=58
o
,m∠O=105
o
,m∠R=90
o
?
=7cm , EW =6cm,∠ N =60
∘
,∠ E =110
∘
and ∠ S =85
∘
.
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