Draw a ∆ PQR in which QR = 6 cm, PQ = 5 cm and PQR = 60°.then construct an another triangle whose side are 3/5 times the corresponding sides of ∆PQR
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Steps are :
1. draw a line segment QR=6cm
2.make a angle of 60° at Q and name the line as P
3. now open the compass of 5cm and put the compass at Q and make a arc on PQ
4. now draw a line QS and open the compass and mark 5 arcs on QS colour name them as Q1, Q2, Q3, Q4, Q5
5. join Q5 and R
6. make a angle at Q5 of same measurement of compass as in 4th step and make a semicircle at Q 3
7. measure the angle of Q5 and mark an arc on Q3
8. now from Q3 draw a line passing through the arc that was made in step7 name the point Q' where it meet QR.
9. make a angled at are with the same measurement of compass as in 7th and make semi circle atQ'
10. measure the angle of Q and mark an arc at Q'
11. draw a line passing through the earth made at Q' and name the point P' where it meet AQ
12. now P'Q'R is the required Triangle
Steps are :
1. draw a line segment QR=6cm
2.make a angle of 60° at Q and name the line as P
3. now open the compass of 5cm and put the compass at Q and make a arc on PQ
4. now draw a line QS and open the compass and mark 5 arcs on QS colour name them as Q1, Q2, Q3, Q4, Q5
5. join Q5 and R
6. make a angle at Q5 of same measurement of compass as in 4th step and make a semicircle at Q 3
7. measure the angle of Q5 and mark an arc on Q3
8. now from Q3 draw a line passing through the arc that was made in step7 name the point Q' where it meet QR.
9. make a angled at are with the same measurement of compass as in 7th and make semi circle atQ'
10. measure the angle of Q and mark an arc at Q'
11. draw a line passing through the earth made at Q' and name the point P' where it meet AQ
12. now P'Q'R is the required Triangle
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