Science, asked by kartikeyapandey19, 1 month ago

draw a punnett squrure list of f1 and f2 generation ( only phenotype) 1. yellow wrinkled seed crossed with green round seed .2) short plant with inflated pod when Crossed with tall plant with constructed pod​

Answers

Answered by omkarjaiswal040
0

Answer:

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

So, the correct option is ‘9:3:3:1

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