Draw a pythagorean triplet whose one number is 15
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Answer:
we know that,
the Pythagorean triple is given as;
(2m, m^2-1, m^2+1)
here , let's that,
= m^2-1=15
=> m^2=16
=> m=√16
=> m=4.
.thus ,.
2m=2×4=8
m^2+1=4^2+1=16+1=17
thus the required Pythagorean triplet is;
(8,15,17)
I hope it would help you
thank you
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