Question

draw a quadrilateral ABCD in which AD and BC are perpendicular on side AB and AB =5cm , AD=7cm , and BC=4cm . hence construct a triangle equal in area of the Quadilateral​

Answer 1

A. Draw the given quadrilateral ABCD.

B. Draw the diagonal DB of quadrilateral ABCD.

C. Draw a parallel line through point C to diagonal DB of quadrilateral ABCD which intersects at Q produced AD.

D. CQ||DB, ΔABQ is the required triangle.

Proof:

∆DCB = ∆DBQ (on same base DB and between same parallels DB and CQ)

∴ ∆DCB = ∆DBQ

∆ABD + ∆DCB = ∆DBQ + ∆ABD (adding area of ∆ABD on both sides)

∴ quadrilateral ABCD = ∆ABQ

Taking BQ as a base, we draw another ∆BCE with one angle 30⁰ and between the parallels DQ and BC.

∴ ∆BCE = quadrilateral ABCD

Answer 2

Answer:

Answer is in the attachment

Step-by-step explanation:

Hope it helps