Math, asked by kuijilo, 9 months ago

draw a quadrilateral ABCD whose vertices are A (3,2) B(2, 3) C(-4,5)and D (5,-4) how to slove

Answers

Answered by amitnrw
6

Given :  a quadrilateral ABCD whose vertices are A (3,2) B(2, 3) C(-4,5)and D (5,-4)

To find :  Draw

Solution:

First Draw  point A

Take 3 unit right of origin  & 2 unit above it  

& mark A = ( 3 , 2)

Then  for B

Take 2 unit right of origin  & 3 unit above it  

& Mark B = ( 2, 3)

Join AB

C -  Take 4 unit left to origin & 5 unit above  it

C = ( -4 , 5)

join BC

D  - Take 5 unit right to origin  & 4 unit below it  

D = ( 5 , -4 )

Join CD   & AD

quadrilateral ABCD is Drawn

its an isosceles trapezium

Slope of AB =   - 1   = Slope of CD =  - 1

BC = AD = √40 = 2√10  unit

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0

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