Draw a quadrilateral ABCD with AB= 5cm , <A=80°, AD =3cm , <D=
120°,
CD= 4cm and draw a triangle of same area?... plz anyone it's urgent , plz explain in the simplest way . I'm writing my exm
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the answer is in below
Step-by-step-explanation. Given,
Construct a quadrilateral ABCDABCD when AB= 5\ cm, BC= 4\ cm,CD= 6\ cm, AD= 3\ cm and BD= 5.5\ cm.AB=5 cm,BC=4 cm,CD=6 cm,AD=3 cmandBD=5.5 cm.
Following steps:
Draw a line segments AB=5\ cmAB=5 cm using scale.
From point AA , draw an arc with 3\ cm3 cm and from point BB , cuts before arc at DD with 5.5\ cm5.5 cm
From point BB ,draw an arc with 4\ cm4 cm measure and from point DD , cuts this arc at CC with 6\ cm6 cm
Join BC,CD and ADBC,CDandAD
Now, ABCDABCD is the required quadrilateral.
By using scale measure the length of ACAC .
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