Question

draw a ray diagram showing the formation of image of a point object by a plane mirror and explain it​

Answer 1

Explanation:

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Answer 2

Answer:

In figure (1), O is an object in front of a plane mirror M1M2. Ray OT from the point 0 incident normally on the plane mirror and reflected back along TO. Another ray OQ incident obliquely on the mirror and reflected along the path QR. If the reflected rays QR and TO are extended backward, they meet at the point I. As if the reflected rays are coming from the point I situated behind the mirror. Therefore, the point I is the virtual image of the point O.

a10

The normal QN is drawn at the point Q.

Since TO and QN are parallel, OQ is the interjector.

So, ˄TOQ = ˄OQN = I …… …….. ……(1)

Again, OI and QN are parallel, line RQI has intersected them.

So, ˄TIQ = ˄NQR = r …… …… ……… (2)

We know, i = r

We get from equations (1) and (2), ˄TOQ = ˄TIQ

Now between ˄QOT and ˄Q1T,

˄TOQ = ˄T1Q, TQ is a common arm,

and ˄QT0 = ˄QTI = 90°

Therefore, the triangles are equal in all respects.

Hence, OT = TI

The image I in a plane mirror is at the same distance behind the mirror as the object O is in front.

Explanation:

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