Question

Draw a ray diagram to get an image by
diverging lens when object is placed at
distance of twice of its focal length 30 cm.​

Answer 1

Answer:

some body please answer this

Answer 2

Given:

An object is placed at a distance twice as that of the focal length of a diverging lens. Focal length is 30 cm.

To draw:

Ray diagram.

Calculation:

Let's calculate the image distance.

Focal length is 30 cm , so object distance will be 30 × 2 = 60 cm.

Applying Lens Formula:

$\rm{\therefore \: \dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u} }$

$\rm{ = > \: \dfrac{1}{( - 30)} = \dfrac{1}{v} - \dfrac{1}{( - 60)} }$

$\rm{ = > \: - \dfrac{1}{ 30} = \dfrac{1}{v} + \dfrac{1}{60} }$

$\rm{ = > \: \dfrac{1}{v} = - \dfrac{1}{30} - \dfrac{1}{60} }$

$\rm{ = > \: \dfrac{1}{v} = \dfrac{ - 2 - 1}{60} }$

$\rm{ = > \: \dfrac{1}{v} = \dfrac{ - 3}{60} }$

$\rm{ = > \: \dfrac{1}{v} = \dfrac{ - 1}{20} }$

$\rm{ = > \: v = - 20 \: cm}$

So, image characteristics:

• Image is virtual.
• Image is diminished.
• Image is erect.

Refer to the attached diagram.

HOPE IT HELPS.