Question

draw a ray diagram to show the formation of an image when an object is placed between F and C in front of concave mirror​

Answer 1

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Answer 2

$\textbf{When \: an \: object \: is \: placed} \\ \textbf{between \: the \: focus(f) \: and} \\ \textbf{centre \: of \: curvature(c) \: of \: a \: } \\ \textbf{concave \: mirror.}$

$\textbf{In \: this \: case - the \: image \: formed \: is : }$

$\textbf{(1)} \: \text{beyond \: the \: centre \: of \: curvature.} \\ \textbf{(2)} \: \text{real \: and \: inverted } \\ \textbf{(3)} \: \text{larger \: than \: the \: object \: (magnified).}$

$\textbf{ \underline{lets \: take \: an \: example \: of \: a \: candle - }}$

If we take a lighted candle as the object and then the image if its which will be formed on a white screen placed at the image position .

If we look at the image A'B', we find that it is wrong side up having arrow-head t its bottom . So, we say that the image is inverted. The size of image is larger than the object, so the image is magnified, and it has been formed beyond the centre of curvature of the mirror .