Question

Draw a rectangle of length 20 cm and breadth 10cm.Name the rectangle and find out the area and perimeter of the rectangle by appropriate formula. ​

Answer 1

Step-by-step explanation:

perimeter

2×(l+b)

2(20+10)

=60cm

area

l×b

20×10

=200cm

Answer 2

Answer :

• The area of rectangle = 200cm²
• The perimeter of rectangle = 60cm

Step-by-step explanation :

To Find,

• Figure, of the rectangle
• Area of rectangle ..... Case 1
• Perimeter of rectangle ..... Case 2

Solution,

Figure,

Given that,

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 20cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 10cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Given that,

• Length of rectangle = 20cm
• Breadth of rectangle = 10cm

Case 1 : –

As we know that,

$\underline{\boxed{ \red{ \bf{Area \: of \: rectangle = l \times b}}}}$

Where,

• l = Length
• b = Breadth

A . T . Q

$\sf{\longrightarrow \: (20 \times 10) {cm}^{2}} \\ \\ \sf{\longrightarrow \: 200 {cm}^{2} \: \: \: \bigstar}$

Hence, area of rectangle is 200cm².

Case 2 : –

As we know that,

$\underline{ \boxed{ \bf{ \red{Perimeter \: \: of \: \: rectangle = 2(l + b)}}}}$

Where,

• l = Length
• b = Breadth

Therefore,

$\sf{\longrightarrow \: \: 2(20 + 10)} \\ \\ \sf{\longrightarrow \: \: 2(30)} \\ \\ \sf{\longrightarrow \: \: 2 \times 30} \\ \\ \sf{\longrightarrow \: \: 60cm \: \: \bigstar}$

Hence, the perimeter of rectangle is 60cm.