draw a rectangle with side 5cm and 3cm. draw a square of the same area.
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Answered by
10
Step-by-step explanation:
Required to construct: A triangle, the area of which = a square with side 5cm
Given: A square ABCD , each side = 5cm
Step 1 : Extend any one side AB of the square, to P, such that AP = 10cm.
Step2: Take an arbitrary point Q on the line coincident to opposite side DC. ( ie extended line DC)
Step3: Join A& Q . Then Join P&Q.
Triangle APQ so formed is the required triangle.
Justification: area( square ABCD) = AB * BC = 25 cm²
area( tri APQ ) = 1/2 * base * corresponding altitude
= 1/2 * AP * BC
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= 1/2 * 10 * 5
= 25 cm²
Answered by
2
Step-by-step explanation:
draw a rectangle with side 5cm and 3cm draw a squar of the same area
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