Math, asked by kuramsettysindhupriy, 4 months ago


draw a rhombus ABCD in which diagonal AC equal to 6 cm and BD equal to 8 cm​

Answers

Answered by dea1233
2

Step-by-step explanation:

1. Draw AC = 8 cm.

2. Draw perpendicular bisector of AC = cut it at I.

3. Cut IB = 6/2 = 3 cm and ID = 3 cm and join ABCD. Then ABCD is the required rhombus.

4. Now from I draw a perpendicular to BC to meet it at L.

5. With I as centre and IL as radius, draw a circle which is the required circle. Its radius = IL = 2.4 cm.

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