Math, asked by nowwwwwhat, 1 month ago

draw a rhombus of side 5cm and one of the angle is 40 degrees draw a triangle of the same area



please help​

Answers

Answered by ITZSAARAVKING
2

Answer:

ans is 42 method is down

Step-by-step explanation:

 \frac{5943? \times \frac{?}{?}  \times \frac{?}{?} }{?}

Answered by yadavanshukumar529
2

Answer:

One side of 5 cm length and one angle of 50° measure are given.

Step -1: Draw a line segment AB of length 5 cm.

Step-2: Draw another line AP such that angle PAB = 50°. Cut off AD = 5 cm from AP.

Step-3: Taking centre at B and D, draw two arcs each of radius 5 cm - that cut one another at point C.

Thus, ABCD is the rhombus having each side of length 5 cm and angle 50°.

Step-4: Connect diagonals AC and BD of the rhombus. Let, AC = m and BD = n.

We know, diagonals of a rhombus are perpendicular bisectors. Area of the rhombus = {(1 / 2) * m * n}. Thus, if we draw a right angled triangle with perpendicular sides of m and n long; area of that right angled triangle equals the rhombus.

Step-5: Draw a line segment PQ = m. Now, draw another straight line at P, PL such that PL is perpendicular to PQ. Cut off PR = n from PL. Join QR to get a right angled triangle PQR, whose perpendicular sides are PQ (= m) and PR (= n).

Area of the right angled triangle PQR = area of the rhombus ABCD.

Similar questions