Math, asked by Akshara987, 1 day ago

Draw a rhombus PQRS with PR = 8 cm and QS = 9 cm and write the steps of construction​

Answers

Answered by Shreya762133
19

Given: PR=8 cm and QS=6 cm.

Steps for construction

Step 1: Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment PR=8 cm.

Step 3 : Draw the perpendicular bisector XY to PR.Let it cut PR at "O".

Step 4 : With O as centre and 3 cm (half of QS) as radius draw arcs on either side of ′O′ which cuts XY at Q and S as shown in fig.

Step 5 : Join

PP , QR , RS and SP.

PQRS is the required rhombus.

Step 6 : We know, PR=d1 =8 cm and QS=d 2 =6 cm.

Calculation of area: In the Rhombus PQRS,

d1 =8 cm and d 2=6 cm.

Area of the rhombus PQRS

=½×d1×d2

= ½×8×6

= 24cm²

HOPE SO IT HELPS YOU

Answered by llchummill
1

Answer:

refer the attachment file mate!

Attachments:
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