Question

draw a right angled triangle

Answer 1

$\mathfrak{dear\;user }$

$\mathfrak{question-}\textsf{to draw a right angled triangle}$

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

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$\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist$

$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

                                                                                    ʙʀᴀɪɴʟʏ  ʀᴏsʜᴀɴ

Answer 2

Step-by-step explanation:

★SOLUTION

• from hint one above we see that M=1;

replace M By 1

S+M sold be at least 10 so as is my mother 9 if there is no carry over from the previous column aur 8 if there is a carry over.

S+Mm can only be 10 or 11 that means O can only be 0 or 1 but O cannot be 1 as M . Hence S=9.

In the hundredth kolam E+O=N,and O=0; but E cannot be the same as N; therefore there must be carried over from the previous column and N must be 1 greater than E:E+1=N.

from the N+R Kollam we can derive the equation: N+R+(+1) =E+10. we have to interest the expression (+1) Vikas we did not know yet another one is carried from over column D+E+10 p is inserted because we do know that one has to be carried over from the column N+R TO E+O.

subtract the first equation from the second: R+(+1)=9.

R cannot be equal to 9 since S=9, therefore R=8; p hence we know that one has to be carried over kolam D+E.

Column D+E mast total at least 12 since Y I cannot be 1 or 0 what values can we give D and E to reach his total? we have already used 9.8 else where the only digits left that are high enoug are 7,6and 7,5. but one of this has to be En,and N is 1 greater than E. hence E=5 and N=6 while D=7.

Then Y=2and the puzzle is solved The solution is:9767+1085=10652.