draw a right - angled triangle in which sides [ other than hypotenuse] are 8cm and 6cm. then is it possible to construct another triangle whose sides are 3/4 times the [corresponding] sides of given triangle?
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Step: I- First of all we draw a line segment let AB = 8cm. Step: II- With A as centre and draw an angle ∠ A = 90°. Step: III- With A as centre and radius AC = 6cm. Step: IV-Join BC to obtain right ΔABC.
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