Math, asked by study11291, 5 months ago

Draw a right angled Triangle of sides 3 cm, 4 cm and 5 cm. Make the squares sheets of 3 cm *3 cm, 4 cm * 4 cm and 5 cm * 5 cm. Fix these squares sheets to the sides of the triangle. Make the squares sheets of 3 cm * 3 cm such that the area should be 9 sq. cm.
Similarly repeat the same thing with the remaining squares sheets.
With this , We can prove the above theorem.
On the above You should consider a= 4 cm, b= 3 cm and c= 5 cm.

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Answered by rogitha18
1

Answer:

Draw a right angled Triangle of sides 3 cm, 4 cm and 5 cm. Make the squares sheets of 3 cm *3 cm, 4 cm * 4 cm and 5 cm * 5 cm. Fix these squares sheets to the sides of the triangle. Make the squares sheets of 3 cm * 3 cm such that the area should be 9 sq. cm.

Similarly repeat the same thing with the remaining squares sheets.

With this , We can prove the above theorem.

On the above You should consider a= 4 cm, b= 3 cm and c= 5 cm.Take a coloured paper, draw and cut a right-angled triangle ACB right-angled at C, of sides 3 cm, 4 cm and 5 cm as shown in fig. (i).

NCERT Class 10 Maths Lab Manual - Pythagoras Theorem 1

Paste this triangle on white sheet of paper.

Draw squares on each side of the triangle on side AB, BC and AC and name them accordingly as shown in figIn a right-angled triangle the square of hypotenuse is equal to the sum of squares on the other two sides.

Concept of a right-angled triangle.

Area of square = (side)2

Construction of perpendicular lines

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