Question

Draw a right triangle in which the (other than hypotenuse) are of length 12cm and 9cm.Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle.

Answer 1

Steps of construction:

1. Draw a line segment BC =4 cm.

2. At B draw ∠B = 90° and cut off BA =3 cm from it.

3. Join AC. Thus ∆ABC is a given right angled Triangle.

4. Now from B draw a ray BY making an acute ∠CBY on the side opposite to the vertex A.

5. Mark 5 points B1,B2,B3,B4 & B5 on BY such that BB1 = B1B2 = B2B3 = B3B4 =B4B5.

6.Join B3C and from B5 draw B5C’ || B3C intersecting BC at C’.

7. From point C’ draw C’A’ || CA intersecting AB at A’. Thus , ∆A’B’C’ is the required triangle whose sides are 5/3 of the corresponding sides of ∆ABC

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