draw a right triangle in which the perpendicular sides are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle
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Step-by-step explanation:
Hey, the figure is attached with the following steps
1. Draw AB of 4cm and AC of 3cm. AC perpendicular to AB.
2. Join BC.
3. Draw an acute angle BAX .
4. Cut it into 5 parts such that AA1=A1A2=A2A3=....
5. Join A3B.
6. measure the angle AA3B And cut the same at A5. From A5, draw a parallel line to A3B.
7. Measure angle ABC and cut the same at angle AB'C. Draw a line parallel to BC.
Here, AB'C' is the required triangle whose corresponding sides are 5/3 tiimes of ∆ABC
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