Draw a right triangle in which the sides are of lenghts 4 cm and 3 cm. Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle. Write steps of construction
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1,Draw a line of AC = 3 cm
2.we can draw angle A = 90
3.With A as centre draw a line of 4 cm we draw arc .Let point arc intersect .
4.Mark the point B and join AB.
5.Draw a ray AY make acute angle with AC .
6.Mark 5 points join A3C and draw a line parallel to A3C,to intersect AC extent at C.
7.Draw a line C' parallel to line BC to intersect AC which extent B'.
8.Now,ABC is a required triangle
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