Question

Draw a rough sketch of a quadrilateral ABCD with diagonals AC and BD.

Find:


(ii) Side opposite to CD​

Answer 1

Answer:

ΔAOB,ΔAOD

DO=OD ( mid point )

AO=OA (common side)

∠AOB=∠AOD (right angle )

So ΔAOB,ΔAOD

So AB=AD

And ∠ABc=∠ADC=90

0

Similarly AB=BC=CD=AD can be proved that ABCD is a square

Step-by-step explanation:

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