draw a schematic diagram of a circuit consisting of a battery of 3 cells of 2 V each,a 4 ohm resistor , an 8 ohm resistor and a 12 ohm resistor , an ammeter and a plug key all connected in series. find the current flowing through the 8 ohm resistor
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- Three cells of potential 2 V, each connected in series therefore the potential difference of the battery will be 2 V + 2 V + 2 V = 6V. The following circuit diagram shows three resistors of resistances 5 Ω, 8 Ω and 12 Ω respectively connected in series and a battery of potential 6 V and a plug key which is closed means the current is flowing in the circuit.
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